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ex/sin(x) may not be integrable generally, because sin(x)=0 for x=nπ, where n is an integer. This creates periodic asymptotes (period is π). The integral of a function is specifically the area under or above a curve with reference to the x-axis, and, since this is an indefinite integral rather than a definite one, this area may not be definable. -1≤sin(x)≤1 but ex rises exponentially and this rise is exaggerated by the fractional nature of sin(x). Therefore the area under the curve or above it when negative is increasing dramatically. If the integral is converted to a definite integral by specifying suitable limits, then it is possible to evaluate the integration using various methods. When x is large negative the curve lies very close to the x-axis as ex→0.

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