intergal of x^5 / root(1+x^3) dx

intergal of x^5 / square root(1+x^3) dx
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Let u2=1+x3, then 2udu=3x2dx, so dx=2udu/(3x2).

∫x5dx/√(1+x3)=∫x5(2udu/(3x2))/u=⅔∫x3du=⅔∫(u2-1)du=

⅔u(u2/3-1)+C=(2/9)√(1+x3)(x3-2)+C.

by Top Rated User (1.2m points)

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