determine the derivative function (dy/dx) for the polynomial function y=square root of x

Question

using the fundamental theorem of calculus, determine the derivative function (dy/dx) for the polynomial function y=square root of x

Answer 1

y square root of x is the same as    x^(-1/2) the derivative of that is -1/2 x ^ (-3/2)

Answer 2

y=suare root of x = x^1/2 Now dy/dx= 1/2 x^ 1/2-1= 1/2x^-1/2=1/2x^1/2