determine the first derivative (dx/dy) of :y = sinx/sec x

determine the first derivative (dx/dy) of :y = sinx/sec x
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2 Answers

y=sin(x)/sec(x)=sin(x)cos(x)=sin(2x)/2

dy/dx=cos(2x); dx/dy=sec(2x)=1/(1-2sin^2(x)) or 1/(2cos^2(x)-1).
by Top Rated User (1.2m points)
y = six/secx = sinx *cosx

d/dx(uv)= d/dxu*v + u*d/dxv

dy/dx=d/dx(sinx)*cosx + sinx*d/dx(cosx) =

            cosx*cosx -sinx*sinx = cos^2x - sin^2x = cos(2x)
by Level 8 User (36.8k points)

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