dy/dt for lnx=e^y +(x^2+y^3)^2-2 if x=1 y=0 & dx/dt=-2

dy/dt for lnx=e^y +(x^2+y^3)^2-2 if x=1 y=0 & dx/dt=-2
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dy/dt=dy/dx * dx/dt.

1/x=e^ydy/dx+2(x^2+y^3)(2x+3y^2dy/dx). Put x=1 and y=0: 1=dy/dx+2(1+0)(2+0), so dy/dx=1-4=-3.

dy/dt=-3*-2=6.
by Top Rated User (1.2m points)

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