x^y=e^x-y , prove that dy/dx= lnx/(1+lnx)^2
in Calculus Answers by Level 12 User (101k points)

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9 Answers

Applying the operator ln^,
by Level 12 User (101k points)
On both sides of the given equality we have:
by Level 12 User (101k points)
Ylnx=x-y
by Level 12 User (101k points)
→ y(1+lnx)=x
by Level 12 User (101k points)
→ y=x/1+lnx
by Level 12 User (101k points)
Therefore, dy/dx_=y'
by Level 12 User (101k points)
= x'•(1+ lnx)-x•(0+1/x)/(1+ lnx)^2
by Level 12 User (101k points)
= 1+ lnx-1/(1+ lnx)^2
by Level 12 User (101k points)
= lnx/(1+lnx)^2
by Level 12 User (101k points)

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