x^y=e^x-y prove dy/dx=lnx/(1+lnx)^2
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8 Answers

Applying the operator ln^,
by Level 12 User (101k points)
On both sides of the given equality we have :
by Level 12 User (101k points)
Y lnx=x-y
by Level 12 User (101k points)
→ y(1+lnx)=x
by Level 12 User (101k points)
→ y= x/1+lnx
by Level 12 User (101k points)
Therefore, dy/dx_= y'
by Level 12 User (101k points)
= x'•(1+lnx)-x•(0+1/x)/(1+lnx)^2
by Level 12 User (101k points)
=1+lnx-1/(1+lnx)^2
by Level 12 User (101k points)

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