Find dy/dx
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Let F equivalence e^ax, G equivalence cos^3x and H equivalence sin^2x : y′=(F•G•H)′= [F•(G•H)]′ = F′•(GH)+F•(GH)′ → y′=F′GH+FG′H+FGH′ F′=ae^ax , G′=-3sinx•cos^2x , H′=2sinx•cosx Therefore: y′=e^ax•sinx•cos^2x•( a sinx•cosx-3 sin^2x+2cos^2x)
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