Find the intergral of sinx*cosx dx
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Question: The integral of sinx*cosx dx.

A double-angle formula is: sin(2A) = 2.sin(A).cos(A)

Hence, sin(x).cos(x) = (1/2).sin(2x)

So int sin(x).cos(x) dx = (1/2) int sin(2x) dx = (1/2)(-(1/2)cos(2x) + const)

Answer: (-1/4).cos(2x) + const

by Level 11 User (81.5k points)

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