tanx +(cosx÷sinx) =1 ÷(sinx × cosx)

RHS equal to LHS. Prove the identity
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tanx +(cosx÷sinx) =1 ÷(sinx × cosx)

lhs = tanx + (cosx / sinx) = sinx / cosx + cosx / sinx = sin^2x / (sinx.cosx) + cos^2x / (sinx.cosx) = (sin^2x + cos^2x)/(sinx.cosx) = 1/(sinx.cosx) = rhs

LHS = RHS

by Level 11 User (81.5k points)
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