seven children each with thesame birthday were born in seven consecutive years .the sum of the ages of the youngest three is 42 what is the sum of the ages of the first three

Question

The question is based on consecutive laws but i can not figurw ouy wat to do

Answer 1

If x is the youngest age then x+1, x+2, etc are the ages of the older children.

The youngest three are x, x+1, x+2. Add them together: 3x+3=42; x+1=14 so x=13. The children's ages go from 13 to x+6=19. (13+14+15=42.) The three oldest are 17, 18, 19 sum=54, and these were the first three to be born. 

1997 1998 1999 2000 2001 2002 2003 (birth year)

  19......18.....17.....16....15.....14.....13 (children's ages in 2016)

......(first born)...................(youngest)