solve for x: log x^8-3

Help me solve for x. logx^8=-3
in Calculus Answers by Level 1 User (140 points)

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1 Answer

Assume log₁₀x⁸=-3,

8log₁₀x=-3,

log₁₀x=-⅜, x=10^-0.375=0.4217 approx.

For a log base of b, x=b^-0.375.

by Top Rated User (1.2m points)

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