log(base2)(2x)+log(base8)(5x)=4

I need to solve/simplify this and I must have exact solutions!!! Please help
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log[2](2x)=1+log[2](x); log[2](8)=3 and log[8](2)=1/3; log[2](x)=3log[8](x); 1/3log[2](5x)=log[8](5x).

log[2](2x)+log[8](5x)=4=1+1/3log[2](x^3)+1/3log[2](5x)=1+1/3log[2](x^3*5x); log[2](5x^4)=3(4-1)=9; 5x^4=512; x^4=102.4; x=3.1811 approx.

 

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