1) (log₂3)(log₃4) = log₂4
[By law of logarithms, {log(base a)b}*{log(base b)c} = log(base a)c]
2) This further simplifies to 2log₂2 = 2 x 1 = 2
[Since 4 = 2^2; log₂4 = log₂(2^2) = 2log2 = 2 x 1 = 2]
3) 3^{log(base3)5} = 5 [BY another law of log, a^{log (base a) b} = b]
4) Thus, log(base2)3 * log(base3)4 +3^log(base3)5 = 2 + 5 = 7