log(x^2+4)-log(x+2)=5+log(x-2)

Question

Find the exact value for the solution and simply the radical.

Answer 1

log(x^2 +4) -log(x+2) -log(x-2)=5

become log[(x^2+4) /(x+2) /(x-2)]=5

if log tu base=10, this become (x^2 +4)/(x+2)/(x-2) =10^5=100,000

or  (x^2 +4)/(x^2-4)=100,000

impli x^2-4 is very kloes tu 0

or x almost=2