find x to this log equation
asked Feb 13, 2015 in Algebra 2 Answers by anonymous

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Log2x+logx=log2x*x=log2x^2=11. 2x^2=10^11 or e^11, depending on whether we are using logs to base 10 or e (natural logs). Let's assume natural logs. So we need ln2=0.69315 approx. lnx=(11-ln2)/2=5.1534 and x=173.02.

answered Feb 13, 2015 by Rod Top Rated User (442,580 points)

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