logarithmic equations log2x-log(x-7)=log3

log2x-log(x-7)=log3

just not sure how to solve it when theres a log on each side with a different log number :)
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1 Answer

Combine the logs on the left: 2x/(x-7)=3. The logs have been removed because if logA=logB then A=B. The equation becomes 2x=3x-21, and x=21. So it wasn't a log question, after all!

by Top Rated User (1.2m points)

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