Can someone give me an explaination of how to solve logarithmic equations.  Here is an example problem.

log2(x^2+x-68)=2
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1 Answer

in exponential form, the equation is 2^2 =x^2+x-68

x^2+x-68 =4

x^2+x-72=0

(x+9)(x-8)=0

x=-9, x=8
by Level 5 User (12.9k points)

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