solve log(5x-1)+log(x+5)=1

Question

Please help me solve this problem.

Answer 1

log(5x+1) +log(x+5)=1

assuming base 10 log, log(10)=1

log(5x+1) +log(x+5)=log[(5x+1)*(x+5)]

so, 5x^2 +26x +5=10

or 5x^2 +26x -5=0

yuze quadratik equashun & gt

x=0.1856777 or x=-5.3856777

-b/2a=-2.6

b^2 -41c=776, so root=27.856776554 & root/2a=2.7856776554

Answer 2

log^x+2=logx3^

Answer 3

Log(5x-1) log(x 5)=1 Log 5x-1/x 5=1 5x-1/x 5=10 cross multiply 5x-1=10(x 5) 5x-1=10x 50 collect like term 10x-5x=50 1 5x=51 dividing through by 5 x=51/5 ans.