solve the simultaneous equations by an algebraic method.

show all your working

3x+4y=19

4x+5y=23
 

 

in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

line 1: 3x+4y =19

line 2: 4x+5y=23

then x+y=4 (me had nonkontrabel erj tu du that)

or from line1, get y=-(3/4)x +19/4

put this in line1.5...(x+y=4)...x-(3/4)x +19/4 =4

or 4x -3x +19=16

x=16-19=-3

so y=4-x=4+3=7
by
Please help me solve these simultaneous equations:

2x - 5y = 19

3x + 7y = -15
by

You’re answering a question with another question. So I’m answering your question as a comment.

Multiply the first equation by 3 and the second by 2:

6x-15y=57

6x+14y=-30

Subtract the first equation from the second above:

29y=-87, y=-87/29=-3.

Go back to either of the two original equations and substitute y=-3:

2x+15=19, 2x=4, x=2.

SOLUTION: x=2, y=-3 satisfies both equations.

Related questions

1 answer
0 answers
1 answer
asked Nov 23, 2011 in Algebra 1 Answers by anonymous | 717 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,289 answers
2,420 comments
741,939 users