You’re answering a question with another question. So I’m answering your question as a comment.
Multiply the first equation by 3 and the second by 2:
6x-15y=57
6x+14y=-30
Subtract the first equation from the second above:
29y=-87, y=-87/29=-3.
Go back to either of the two original equations and substitute y=-3:
2x+15=19, 2x=4, x=2.
SOLUTION: x=2, y=-3 satisfies both equations.