solve using method of elimination 6 + 2/3x=1/4y 1/3x+2y=14
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line 1: (2/3)x=(1/4)y, or (8/3)x=y . . . line 2: (1/3)x+2y=14, or x+6y=42 . . . x+6*(8/3)x=42 . . . x+(48/3)x=42 . . . x+16x=42 . . . x=42/17=2.470588235... y=(8/3)x=336/51 =6.588235294
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"Rounded
Solution: Given eliminate 6 + 2/3x=1/4y..........(1)
1/3x+2y=14 …........(2)
standard form
2x/3-y/4=-6.....(1)
x/3+2y=14....(2)
subtract 1/2*(equation 1) form equation (2)
17y/8=17
there for y=8
substitute y=8 in equation (1)
we get x=-6 "


A set of independent equations in two or more variables is called a simultaneous equation. To find the value(s) of the variables for which the set of equation holds is called solving the equation. There are different methods used to solve simultaneous equations. In this article, we will learn how to solve the Solving Simultaneous Equations by Substitution and Elimination methods with examples.
by Level 4 User (5.6k points)

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