solve the system by the elimination method 3x=5y+2 3y=5x-14

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Best to get your unknowns on to one side of the equation:
3x-5y=2; 5x-3y=14. To eliminate x or y we need first to multiply each equation by 3 or 5 so that we end up with a matching x or y coefficient in each equation.
That is, 15x or 15y. Let's multiply by 3 and 5:
9x-15y=6; 25x-15y=70.
The y terms have the same coefficient, so let's subtract the first equation from the second.
16x=64, so x=4 and 20-3y=14, by substituting x. So 3y=6 and y=2.
Check out these values by putting them into the original equations.
by Top Rated User (1.2m points)

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