9x^2+4kx+5=0 ,, find the value of k?
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(3x+5)(3x+1)=9x2+18x+5=0, so 4kx=18x, k=9/2;

(9x+1)(x+5)=9x+46x+5=0, so 4kx=46x, k=23/2;

(9x+5)(x+1)=9x2+14x+5=0, so 4kx=14, k=7/2.

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