For the equation k^u/k^2w=k^8 and (k^3)^w/k^u=1. If k > 0, what is the value of u?

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 ​Equating exponents: u-2w=8 and 3w-u=0 (k⁰=1). Therefore u=3w, 3w-2w=w=8, so u=3w=24.

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