Calculus matrices
asked 6 days ago in Calculus Answers by Bj

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1 Answer

 

  1. w+x+y+z=1
  2. w+x-y-z=7 is the same as 2w+2x-2y-2z=14
  3. w-2x+2y+z=9
  4. w-x+7y+5z=-15

Add (1) and (2): 2w+2x=8, that is, w+x=4, w=4-x.

Subtract (2) from (1): 2y+2z=-6, that is, y+z=-3, z=-3-y=-(3+y).

By substituting for w and z in (3):

(4-x)-2x+2y-(3+y)=9 simplifies to -3x+y=8 (5); and in (4):

(4-x)-x+7y-5(3+y)=-15, 4-2x+7y-15-5y=-15, -2x+2y=-4, -x+y=-2, y=x-2.

By substituting for y in (5):

-3x+(x-2)=8, -2x=10, x=-5, and y=-7, w=9, z=4 from other equations in bold print.

 

answered 6 days ago by Rod Top Rated User (552,780 points)

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