*The equation for line j can be written as 9x − y = 10. Line k is perpendicular to line j and passes through (-8, 1). What is the equation of line k in slope-intercept form?*

The product of the slopes of perpindicular lines is -1.

i.e. if slope of line k is m1 and slope of line i is m2, then m1*m2 = -1.

For line i, 9x - v = 10, or, v =9x - 10, therefore slope,__ m2 = 9__

Line k is perpindicular to line i, therefore m1 = -1/m2 =__ -1/9__

Line k passes through (x,v) = (-8, 1), therefore we can write,

(v - 1) / (x - (-8)) = m1 = -1/9

9(v - 1) = (-1)(x + 8)

9v - 9 = -x - 8

9v = -x +1

**In slope-intercept form, teh equation of line k is: v = -x/9 + 1/9**