This is a cartesian plane question: Find the equation for the line that is perpendicular to line  y = 2x-3 and passes through the point (1,4)
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A perpendicular line has the opposite slope to the given line, which has a slope=2, the x coefficient. The perpendicular slope is -½, because the product of the two slopes has to be -1.

We can use the slope-intercept form of a line to find its equation, plugging in the given point:

y-4=-½(x-1), y=-½x+½+4=-½x+9/2. This can be written in different ways:

2y=9-x, 2y=-x+9, x+2y=9, x+2y-9=0, y=½(9-x). All these are equivalent.

 

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Hi Rod

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regards

Danny Hayden

Melbourne, Australia,

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