A friend of mine asked if i can solve her this question and never respponded that i dont know calculos so i dont want to let her fail so can you answer this quick please?
in Calculus Answers by Level 1 User (840 points)
PLeaassse  o one answered yet oh come ON jishka Jomework ansers answer FAST!

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1 Answer

First, we need to find out where the curve meets the x-axis (y=0), so it’s clear that x=0 and x=3 are the limits.

We can write the area as an integral: ∫ydx[0,3] where the limits are in square brackets.

Substitute for y: ∫(3x⁵-x⁶)dx=(x⁶/2-x⁷/7)[0,3]=3⁶(1/2-3/7)=729/14=52¹⁄₁₄ or 52.07͒14285͒ where   ͒  indicate a recurring  decimal.

The curve in red is a thin sliver between x=0 and x=3 as shown. The required area is clearly seen.

by Top Rated User (616k points)

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