Help please thanks sirs

d) So ∂=±ɛ/4. The variation of x is <∂ or (2-ɛ/4,2+ɛ/4). Therefore a) ɛ=1, ∂=±0.25 b) ɛ=0.4, ∂=±0.1 c) ɛ=0.08, ∂=±0.02.

4. Similarly, when x=1, 5(x+∂)-3=2±ɛ⇒5(1+∂)-3=2±ɛ, (d) ∂=±ɛ/5 a) ±0.2 b) ±0.1 c) ±0.002. The variation of x is <∂ or (1-ɛ/5,1+ɛ/5).

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