Help please thanks sirs

Best answer

1a) 2x+1=7+1=8, so x=7/2; 2x+1=7-1=6, so x=5/2. So 5/2<x<7/2, x=(2.5,3.5) or x=3±0.5. 0.5 is half a unit.

b) the clue is to halve the difference specified for the limit, so x=3±0.3, then 2x+1=7±0.6 or x=(2.7,3.3) or 2.7<x<3.3.

c) x=3±0.02, x=(2.98,3.02) or 2.98<x<3.02 d) x=3±ɛ/2, x=(3-ɛ/2,3+ɛ/2) or 3-ɛ/2<x<3+ɛ/2.

2a) x=1±⅓, x=(⅔,1⅓) or ⅔<x<1⅓ b) x=1±0.2,... c) x=1±0.03,... d) x=1±ɛ/3,...

where ... simply means the alternative formats: () or inequality. To be within the limits the ± format may need to be omitted because it implies less than or equal instead of less than.

- All categories
- Pre-Algebra Answers 12.4k
- Algebra 1 Answers 25.4k
- Algebra 2 Answers 10.5k
- Geometry Answers 5.2k
- Trigonometry Answers 2.7k
- Calculus Answers 6.1k
- Statistics Answers 3k
- Word Problem Answers 10.2k
- Other Math Topics 6.8k

82,168 questions

86,659 answers

2,246 comments

76,270 users