Please solve ASAP please thanks alot

asked Feb 8 in Geometry Answers by Joseph

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(x+1)³=x³+3x²+3x+1, therefore the limit is x²+3x+3➝3 when x➝0. The limit is 3.

x⁵-1=(x-1)(x⁴+x³+x²+x+1) so the denominator divides into the numerator leaving x⁴+x³+x²+x+1➝5 as x➝1. Limit is 5.

answered Feb 8 by Rod Top Rated User (570,580 points)

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