Please help me solve this.. thanks in advance..

Express the solutions for x as logarithms: 10^(2x)-5(10^x)+6=0
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Let y=10^x: y^2-5y+6=(y-3)(y-2)=0, y=3 or 2.

10^x=3 or 2, x=log(3) or log(2). (Logs to base 10.)
by Top Rated User (1.2m points)

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