differential equations : Eliminate constants C1 and C2
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y=C1e^x+C2xe^x

y'=C1e^x+C2xe^x+C2e^x

y"=C1e^x+C2xe^x+2C2e^x

Require equation y"+ay'+by=0; C1e^x+C2xe^x+2C2e^x+aC1e^x+aC2xe^x+aC2e^x+bC1e^x+bC2xe^x=0.

Therefore, since e^x cannot be zero, we can divide through by e^x:

C1+C2x+2C2+aC1+aC2x+aC2+bC1+bC2x=0=C2(1+a+b)x+C1(1+a+b)+C2(2+a).

We need to make the coefficients of C1 and C2 zero by choosing suitable a and b.

From this 2+a=0, so a=-2, 1+a+b=0=-1+b, b=1.

y"-2y'+y=0 is a second order DE that doesn't contain C1 or C2 but satisfies y.
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