Matthew wants a bigger cage for his bearded dragon. He wants to length to be 2 inches less than twice the width. If the perimeter of the cage should be 104 in, what dimensions should the cage be

Matthew wants a bigger cage for his bearded dragon. He wants to length to be 2 inches less than twice the width. If the perimeter of the cage should be 104 in, what dimensions should the cage be?
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Perimeter=2L+2W=104, making L+W=52, where L=length and W=width. L=2W-2 so 2W-2+W=52. 3W=54 and W=18", and L=2W-2=34". Cage length is 34" and width=18".

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