x+a =b+c​

 

  a       c      solve for x 

 

              the answer is x=a+b

 

     ​                                     c

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2 Answers

For this question, you simply need to multiply both sides by (b-c) to get: 

a(b-c) = x <==== FINAL ANSWER 

I hope that helps you out! Please let me know if you have any other questions!
 
Source(s):College Calculus Student ; Math Tutor
by Level 10 User (57.4k points)

OK, Priscilla, let's see.

I think this is what the question is: (x+a)/a=(b+c)/c. In words, this is: the sum of x and a divided by a equals the sum of b and c divided by c. Is that right? Treat a, b and c as if you knew what numbers they represent,

We want to end up with x on one side of the equals and a, b and c on the other.

We need to get rid of the fractions. On the left we have a in the denominator, so if we multiply both sides by a, the one on the left will cancel out: x+a=a(b+c)/c. Now expand the right side: x+a=(ab+ac)/c. We still need to get the a on the left over to the right, so we subtract a from each side:

x=(ab+ac)/c - a.

Now we have a fraction and a whole number on the right. We need to combine these by placing everything over the same denominator, c. Now, a is the same as a/1, so we divide 1 into c and we get c, of course, so we multiply c by the numerator a to give ac (ac/c=a). What we have now is: x=(ab+ac-ac)/c. So ac cancels out and we're left with x=ab/c. 

Alternatively, cross-multiply: c(x+a)=a(b+c); cx+ca=ab+ac. ca=ac so these terms cancel: cx=ab, x=ab/c.

I've presented this answer as simply as I can, so I apologise if it's too simple, and you may be able to skip a couple of steps if you understand what's going on.

by Top Rated User (1.2m points)

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