I have all of the working out but i dont understand how the answer works as the roots are where the graph crosses the x axis but  f(x) = x^2 + 1 does not cross the x axis can someone please explain.

1.  x^2 + 1 =0

2.  x^2 = -1

3.  square root (x^2) = square root (-1)

4.  x = square root (-1)

5.  x = + or -  i
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

trick question.  There are no real roots to x^2 + 1
by

Related questions

1 answer
asked Mar 10, 2013 in Trigonometry Answers by anonymous | 929 views
1 answer
asked Dec 13, 2012 in Algebra 2 Answers by anonymous | 771 views
1 answer
1 answer
1 answer
asked Jan 31, 2012 in Algebra 2 Answers by jrgwesljs Level 1 User (280 points) | 770 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,515 questions
100,352 answers
2,420 comments
765,024 users