solve 6y^2+y/2y^2-9y+9-2y+p/2y^2-9y+9-4y-3/V

Question

how would you work this problem?

Answer 1

I think the expression should read:

(6y²+y)/(2y²-9y+9)-(2y+9)/(2y²-9y+9)/(2y²-9y+9)-(4y-3)/(2y²-9y+9).

(I guess V should have been Ctrl+V key operation for paste and p should have been 9.)

The three fractions have a common denominator so the numerators can be added:

(6y²+y-(2y+9)-(4y-3))/(2y²-9y+9),

(6y²+y-2y-9-4y+3)/(2y²-9y+9),

(6y²-5y-6)/(2y²-9y+9),

(2y-3)(3y+2)/((2y-3)(y-3)),

(3y+2)/(y-3) provided y is not equal to 3/2 (=1½).

So the expression simplifies to (3y+2)/(y-3).