If 4x+4y+2z=560 and 9x+9y+6z=1290.Than x=,y=,z=

If a man bought 4 shirts,4 pants, 2 hats for $560.00.Went back bought 9 shirts,9 pants,6 hats for$1290.How much did he pay for 1 shirt,1 pants,1 hat?
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1 Answer

Divide 1st equation by 2: 2x+2y+z=280

Divide 2nd equation by 3: 3x+3y+2z=430

Subtract the first of these from the second: x+y+z=430-280=150.

So he paid $150 for 1 shirt, a pair of pants, 1 hat.

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