solve for x,y,z x+y+z=4, x+y+2z=5, 4x+4y+6z=18

solve system of linear equations with three variables
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2 Answers

anser: z=1 & x+y=3
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Given x+y+z=4,...(1)
x+y+2z=5, ...(2)
4x+4y+6z=18...(3)
Mutiply (1) by -1 and add with equation (2)
-x-y-z=-4
x+y+2z=5
---------
z = 1
Substituting z value in equation (1)
x+y=3
x= 3-y

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by Level 8 User (30.1k points)

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