whats the integrale of ((tan x)/(sec x))dx

Question

its a question on integration that forms part of the integraln ((9(x^2)-1)^0,5)/(x^2+x))dx

Answer 1

The integral of (tan x)/(sec x)dx. The inverse of sec x is cos x, so the question becomes tan x.cos x. But tan x is sin x / cos x, therefore tan x.cos x is just sin x, the integral of sinx dx is simply -cos x.