Tan theta /(sec theta-1) tan theta /(sec theta 1) = 2 cosec theta
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1 Answer

mi ges be yu tri tu sae

[tan(x) /sekant(x-1)]^2=2* kosekant(x)...2*csc(x)...=2/sine(x)

sekant=1/kosine, so 1/sekant=kosine

tan=sine/kosine, so tan*kosine=(sine/kosine)*kosine=sine

but yu hav tan(x)*kosine(x-1), so kant kansel stuf

 

Thats as far as me get...dont no wot tu du next
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