integral (1 - tan^2 x)\(sec^2 x) dx

Could ues some help on this calculus problem.  Not sure where to start.
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1 Answer

integral((1-tan^2(x))/sec^2(x)dx)=integral((cos^2(x)-sin^2(x))dx)=integral(cos(2x)dx)=(1/2)sin2x+k, where k is a constant of integration.

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