parabola an straight line
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2x^2+4x+y=0 become y=-2x^2-4x...parabola belo x-axis

line y=2x=strate line that go up on rite side av y-axis

Assuming yu start at x=0 & want the part for x gotu a positiv number a...

add the areas: line alwaes abuv x-axis & parabola belo it

strate line make triangel so area=xmax*ymax/2 & ymax=2*xmax, so that area=xmax^2

area belo x-axis...integrate -2x^2-4x...-(2/3)x^3-2x^2 from x=0 tu x=xmax

become -(2/3)xmax^3-2xmax^2

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