Find dy dx using implicit di erentiation: x 2 y 2 + x sin y = 1

finding dy dx
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1 Answer

x2y2+xsin(y)=1,

2xy2+2x2ydy/dx+sin(y)+xcos(y)dy/dx=0,

2x2ydy/dx+xcos(y)dy/dx=-2xy2-sin(y),

dy/dx=(-2xy2-sin(y))/(2x2y+xcos(y)).

by Top Rated User (1.2m points)

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