f(x)=(2x²-8)(x-2)=2(x-2)(x+2)/(x-2)=2(x+2), provided x≠2. So in the limit as x➝a, when a=2, f(x)➝8. The function is not defined at x=2 because we have 0/0 when the function is evaluated. There is a hole at x=2, making it undefined and therefore discontinuous.