three consecutive odd integers such that the sum of the first and second is 31 less than 3 times the third. find the integers
The numbers are n, n+2 and n+4
(3 * (n+4)) - 31 = n + (n+2)
3n + 12 - 31 = 2n + 2
3n - 19 = 2n + 2
3n - 2n = 2 + 19
n = 21
n+2 = 23
n+4 = 25
n + (n+2) = 21 + 23 = 44
(3 * (n+4)) - 31 = (3 * 25) - 31 = 75 - 31 = 44
The three numbers are 21, 23 and 25 (sorry about that, Fermat)