such that the s f the first and second is 31 less than 3 times the third. find the integers
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

Find  three consecutive odd integers such that the sum of the first and second is 31 less than 3 times the third.

Let teh 3 numbers be n1, n2, n3.

And n3 = n2 + 2, n2 = n1 + 2  (since they are consecutive (odd) integers)

We are told that,

n1 + n2 = n3 - 31

n1 + (n1 + 2) = (n1 + 4) + 31

n1 = 33

n2 = 35

n3 = 37

by Level 11 User (81.5k points)
n1 + n2 = 33 + 35 = 68
n3 - 31 = 37 - 31 = 6   ????
Even n3 + 31 is wrong.
The problem says (3 * n3) - 31
(3 * 37) - 31 = 80
three consecutive odd integers such that the sum of the first and second is 31 less than 3 times the third. find the integers

The numbers are n, n+2 and n+4

 (3 * (n+4)) - 31 = n + (n+2)

3n + 12 - 31 = 2n + 2

3n - 19 = 2n + 2

3n - 2n = 2 + 19

n = 21

n+2 = 23

n+4 = 25

n + (n+2) = 21 + 23 = 44

(3 * (n+4)) - 31 = (3 * 25) - 31 = 75 - 31 = 44

The three numbers are 21, 23 and 25  (sorry about that, Fermat)
by Level 11 User (78.4k points)
Well spotted CWA. Thanks for giving the correct solution.

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,240 questions
90,465 answers
2,120 comments
78,588 users