the three consecutive integers are
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2 Answers

n*(n+1)*(n+2)=n^3+208

n^3 +3n^2 +2n=n^3+208

3n^2 +2n=208

3n^2 +2n -208=0...yuze quadratik equashun

roots=8 or -8.66666666

yuze 8..8*9*10=720

8^3=512

720-512=208
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The product of 16 and 14 less than a number is 208
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