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Find two consecutive even integers such as that the smaller added to two times the larger gives a sum of 34.

even integers are multiples of 2.

Let the two consecutive even integers be n1 and n2. Then ...

n1 = 2n,   n = 1,2,3,...

n2 = 2(n+1),    n = 1,2,3,...

n1 + 2*n2 = 34      (the smaller added to two times the larger gives a sum of 34)

2n + 2*{2(n+1)} = 34

2n + 4n + 4 = 34

6n = 30

n = 5

The two numbers are: m1 = 10 and m2 = 12

by Level 11 User (81.5k points)

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