two consecutive odd numbers such that 6 times the smaller added to 4 times the greater comes to 138 .
Let the two numbers be n1 and n2,
where both n1 and n2 are odd
and n2 = n1 + 2. (since they are consectutive numbers)
We are told that,
6*n1 + 4*n2 = 138
3n1 + 2n2 = 69
3n1 + 2(n1 + 2) = 69
3n1 + 2n1 + 4 = 69
5n1 = 65
n1 = 13
n2 = 15