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two consecutive odd numbers such that 6 times the smaller added to 4 times the greater comes to 138 .

Let the two numbers be n1 and n2,

where both n1 and n2 are odd

and n2 = n1 + 2. (since they are consectutive numbers)

We are told that,

6*n1 + 4*n2 = 138

3n1 + 2n2 = 69

3n1 + 2(n1 + 2) = 69

3n1 + 2n1 + 4 = 69

5n1 = 65

n1 = 13

n2 = 15

by Level 11 User (81.5k points)

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