How find a simplest Boolean expression for (x' ^ y‘ ^ z')v(x' ^ y' ^ z)v(x ^ y' ^ z')v(x ^ y ^ z')

Boolean Expression
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1 Answer

This can also be written and factored:

x'y'z'+x'y'z+xy'z'+xyz'=x'y'(z'+z)+xz'(y'+y);

z'+z=y'+y=1;

So this simplifies: x'y'+xz' or (x'∧y')∨(x∧z').
by Top Rated User (1.2m points)

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